36x^2+24x-5=0

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Solution for 36x^2+24x-5=0 equation: 



36x^2+24x-5=0

a = 36; b = 24; c = -5;
Δ = b2-4ac
Δ = 242-4·36·(-5)
Δ = 1296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1296}=36$


$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(24)-36}{2*36}=\frac{-60}{72}
=-5/6
$


$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(24)+36}{2*36}=\frac{12}{72}
=1/6
$

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